Definition 11Big-Of(n)=O(g(n))f(n) = O(g(n))f(n)=O(g(n)) means there are constants c>0c > 0c>0 and NNN with f(n)≤c⋅g(n)f(n) \le c\cdot g(n)f(n)≤c⋅g(n) for all n≥Nn \ge Nn≥N.